v = 1. That is the only force in the horizontal plane, so that is equal to the mass A body of mass m is rotated along a vertical circle of radius r such that velocity of the body at a point of vertical circle is equal to critical velocity at that point then: A) maximum change in K. Jun 18, 2021 · Here we have given NCERT Solutions for Class 11 Physics Chapter 5 Laws of Motion. 45 m. Question 1. Question: A 34-g ball at the end of a string is swung in a vertical circle with a radius of 27 cm. at the bottom of the circle Tbottom N. A stone, of mass m, is attached to a strong sting and whirled in a vertical circle of radius r. 0 = m (v 2 /r) - mg. It continues moving in a circle, keeping the bob exactly the same distance from the pivot. 0-m rope is moving in a vertical circle. The string can withstand a tension of 14. Calculate the frequency. 03 m-long string. And when the rope is pulling in the body, the body can only move in a circular path. Unless this force is present, no object can execute a pure circular motion, because in absence of a force, a body moves uninterrupted along a straight line (Newton's first law). Substituting these values into the formula, we get:Fc = (0. Question: Part A A 700 g ball moves in a vertical circle on a 1. Lesson Takeaways. I know that the answer is (B) 2mg, I just don't know why. 1 N. 00 m long rope in a complete vertical circle. This is due to the forces of tension and gravity working together at the top and in opposition at the bottom. 75 m long string and being swung in a vertical circle at a constant speed of 5 m/s a) What is the tension in the string at the top of the vertical circular path? b) What is the tension in the string at the bottom of the circular path? Aug 19, 2015 · A tension less than zero isn't really physical; this is the point where the string stops being taught and the object doesn't make a complete circle. If the tension at the top is found to be 0; A 0. Jul 24, 2018 · Minimum velocity v= 3. 0 N Part A Find the speed of the bucket. The body starts whirling in a vertical circle. 95 m/s, The velocity of stone when the string is horizontal = 3. Physics questions and answers. The centripetal or normal acceleration of particle at highest point is a n = 10 p m / s 2 . This force creates tension in the string, as the string is being pulled towards the center along with the ball. A body of mass 0. A pendulum bob of mass m is suspended by a massless string and at rest when string is vertical. If its speed is 6. at the top of the circle Ttop N b. Find the tension in the string: a. 8 m. a) What is the ball's weight? b) What is the tension in the string when the ball is at the top? c) What is the tension in the string when the ball is at the bottom? There are 2 steps to solve this one. I can determine the magnitude and direction of the forces needed for the overall centripetal force. E. Gravity pulls down, normal force pushes up. How fast must the bucket move at the top of the circle so A stunt pilot of mass 80 kg flies in a vertical circle of radius 350 m at a constant speed of 70 ms-1. Explain why there's a minimum speed to keep the ball moving in a circle. As the ball swings down, the tension in the string increases, reaching a maximum at the bottom of the circle. A small mass mm is tied to a string of length L and is whirled in vertical circular motion. 7 shows an object moving in a circular path at constant speed. b) How fast must the bucket move at the top of the circle so that the rope does not go slack? At the top and bottom of the vertical circle, the ball's speeds are vt and Ub and the corresponding tensions in the string are T'; and Th. 10 m. 61 NTherefore, the tension in the string at the top of the circle is 1. This is why the string doesn’t feel as taut (tight) at the top of the swing. the velocity at the bottom is vbottom = m/s. d. 60 kg is whirled in a vertical circle of radius 1. What is the magnitude of the tension in the string at this position? There are 2 steps to solve this one. 8 = 1120 – 784 = 336 N m (v 2 /r) = T + mg. $\endgroup$ – Dec 27, 2020 · A 5. b) What is this speed at the bottom of the Mar 28, 2024 · One way to have a force that is directed towards the center of the circle is to attach a string between the center of the circle and the object, as shown in Figure 6. (a) What is the tension in the string when the ball is at the top of the circle if its speed at that point is 3. 33 m/s)²/0. That is because the rod is rigid and Science. So, the tension in the rope will become zero. A stone is tied to a rope is rotated in a vertical circle with unifrom speed. If the speed at the top is 4. Click here👆to get an answer to your question ️ 15. the difference between the tension at the bottom of the circle and the tension at the top of circle is a) 4mgb) 0c)2mgd) 6mge) 3mg. B) How fast must the bucket move at the top of the circle so that the rope does not go slack? Centripetal force, for an object in circular motion, is just the force maintaining the circular motion, the force that prevents the object from flying away tangentially. 0 m with a revolution time of 0. At the lowest point of its motion the tension in the rope supporting the bucket is 30. (Take g = 9. The speed of the mass v is such that the ratio of the string tension at the top of the circle to that at the bottom of the circle is FTtop/FTbot = 0. 50 m/s? (b) What is the maximum speed the ball can have at the bottom of the The centripetal force points toward the center of the circle. 25 m/s ; at the bottom of the circle its speed is 6. 00 kg is whirled in a vertical circle of radius 1. b. in the video, he writes down Newton's 2nd Law in the x-direction, which is the direction that is toward the center since the circle is horizontal. What is the tension in the rope at the top of the swing if the speed of the object is 4. 137 kg)(2. Substitute the values in the above equation. 0 cm/s. What is v? What is the period of the circular motion? Express your answer with the appropriate units. May 27, 2016 · In the case of the water in the bucket, it's inertia would take it in a straight line, gravity modifies that into a parabola, but the sides and bottom of the bucket are moving in a circle for both those things to be true (the bucket goes in a circle and the water goes in a parabola) the water would have to move through the bottom of the bucket. Give an everyday example of circular motion for which the centripetal acceleration is A bucket of mass 1. At the exact top of the path the tension in the string is 3 times the stone's weight. May 20, 2020 · 0 $\begingroup$ I know that for a body to complete motion in a vertical circle, the initial velocity at the lowest point must be such that the tension at the highest point is zero, what if the velocity is greater than the said value and the tension at the highest point is not zero? Dec 4, 2015 · At the top of the path, the pail exerts a normal force on the water, directed downwards. So the direction towards the center is down and to the left. Derive an expression for the speed v. A) Find the speed of the bucket. A bucket of mass 2. A 0. 00 m/s at the top of the circle, the tension in the string has a magnitude of: There are 2 steps to solve this one. 0 N before breaking. 25 kg steel ball is tied to the end of a string and then whirled in a vertical circle at a constant speed v. 5 cm from the center of the circle (r = 12. 3. May 16, 2016 · 2) If the velocity ends up = 0 = 0 at θ = 0 θ = 0, then the tension T = m02/2 − mg T = m 0 2 / 2 − m g which would end up giving tension a negative value. A particle of mass m =2 kg is suspended by a string of length l =1m is whirled in a vertical circle about point O. Give the magnitude and direction of the net force acting on. A rock is tied to the end of a string and whirled around in a circle that describes a vertical plane. If the radius of circle is 0. B. (d) a car moving with a constant velocity of As you do, the normal force will become less. Neglecting air resistance, what is the difference between the string's tension at the bottom of the circle and at the top of the circle? (A) 1mg (B) 2mg (C) 4mg (D) 5mg (E) 6mg. This combined with the force of gravity gives us a centripetal force that keeps the entire pail-water system moving in a circle. But I'm taking my y-axis towards the center, and my x-axis tangent to the circle. 10 m long cord (negligible mass) is swung in a vertical circle. . But if you swing too slowly, the string goes slack as the ball nears the top. At the lowest point of its motion the tension in the rope supporting the bucket is 22. the difference between the magnitude of the tension in the string at the bottom relative to that at the top of the circle. How fast must the bucket move at the top of the circle so that the rope does not go slack? A bucket of mass 2. 8 N. 8 N 10. a) Find the speed of the bucket. 0 cm. 0 m rope and whirled in a vertical circle with a constant speed 10 m/s. What is the tension in the rope if the block is whirling in a horizontal circle of radius 2. If the string is under tension, the force of tension will always be towards the center of the circle. 0; 1. 75 m. 14it slide down At what height 'h' from 16. 02m -long string. 5-kg object is moving in a vertical circular path on a string 0. A constant horizontal force F = mg starts acting on it. Find the tension in the string: (a) at the top of the circle, (b) at the bottom of the circle, and (c) at a distance of 12. It takes less of a normal force to constrain the car into the circular path because gravity gets to act on the car longer as it ascends higher. 0 N . -T. 05 m . Find the tension in the rope tied to the bucket at the top of the circle. at $\theta = \pi$. Nov 17, 2015 · No, tension varies at different points in circular motion. 0-cm-long string in a vertical circle. Acceleration is in the direction of the change in velocity; in this case it points roughly toward the center of r If its speed is 6. There are 2 steps to solve this one. May 9, 2023 · Why is tension 0 at the top of a vertical circle? This is the lowest body velocity necessary for the body to circle a loop, or travel around the circle once entirely. May 6, 2023 · Tension and gravity are NOT “in the same direction”. The rotational velocity is 200. Give a reason for your answer. Mar 28, 2017 · At the top of a circle, the ball is experiencing a centripetal force towards the center of the circle. For a mass moving in a vertical circle of radius r = m, For a velocity at the top vtop = m/s. A 30. 81 m / s 2 v = 11. A bucket of mass 1. (b) a cork of mass 10 g floating on water. The forces on the object are thus: →Fg. What is the tension in the string at the top of the circle? Take g = 1 0 m s − 2 A 500 g ball moves in a vertical circle on a 102 cm long string. 0 kg ball is attached to a 1. 62 mm, and the tension in the string when the ball is at the top of the circle is 4. How fast must the bucket move at the top of the circle so that the rope does not go slack? Here’s the best way to solve it. Centripetal force (F_c) is given by the equation F_c = m*v^2/r, where m is the mass of the object, v is the speed of the object, and r is the radius of the circle. The normal force is less than the gravitational force because the hill is curving downward away from the bike, and the bike is accelerating downward. That's why it's called centripetal. Calculate the speed of the object. 43 m / s. If the speed at the top is 3. ve marks questions A string 0. (c) a kite skilfully held stationary in the sky. A 5 kg object travels in a vertical circle of radius 10 m at constant speed of 15m/s. Example – 02: A stone weighing 1 kg is whirled in a vertical circle at the end of a rope of length 0. At the lowest point of its motion the tension in the rope supporting the bucket is 33. At highest point C, tension is minimum. Why is tension 0 at the top of a vertical circle? Feb 10, 2022 · The mass of the object is 0. 5 m/s. The tension in the rope is always directed toward the middle of the circle. 8 ms-2) Calculate the force of the seat on him at: (a) the top of the circle (b) the sides of the circle when he is moving vertically (c) the bottom of the circle (a) T = mv 2 /r – mg = 80x70 2 /350 – 80x9. So we see that the centripetal force in this case is the horizontal component of the tension, Tx = Tsin (30). At the highest point, it falls downward. (a) Find the speed of the bucket. Here's an appropriate free-body diagram I found online: (ignore the "bottom of circle" portion) It means all bodies (whether an iron ball or a piece of paper), when dropped (u = 0) from same height should fall with the same rapidity and should take the same time to reach the earth, i t is the minimum velocity given to the particle at the lowest point to complete the circle. 0 + m g = m v min 2 r m g = m v min 2 r v min 2 = g r v min = g r This is the minimum velocity also called as A bucket of mass 1. 83 m/s, The velocity of stone at the topmost point = 2. Expert-verified. We can draw a diagram of the ball swinging in a vertical circle on the end of a string. Science. At the top of the circle the speed of the object is 4. 30-kg bucket of water in a vertical circle of radius 0. 5 kg is whirled in a circle with a velocity of 2 m/s using a 0. Question: A 5 kg object travels in a vertical circle of radius 10 m at constant speed of 15m/s. It is greatest at the bottom of the circular path, and decreases as the object moves towards the top. Thus, the speed of the bucket at the top of the circle is 3. Nov 21, 2023 · For an object tied to a string as it moves in a vertical circular motion, the tension at the bottom can be calculated using the equation below: Tension at the bottom of the circle = m (vB)^2/r If the mass of the bob is m, then tension in the string is mg cosθ. (b) Calculate the tension in the cord at the bottom of the arc if the ball is moving at twice the speed of part Science. I can qualitatively describe how tension changes in a vertical circle. 25-kg mass is attached to a string and swung in a vertical circle whose radius is 0. If the same 10 kg block were whirled in a vertical ANS: 3. This tension is less than we calculated in part (a), so if the string is strong enough to swing the ball through the bottom of the swing, it will certainly be strong enough at the top of the swing. What is the magnitude of gravitational force acting on Oct 13, 2023 · Suppose a body is attached to a string, and is whirled around along a vertical circular path. At the highest point of the circle, the tension in the string is equal to the weight of the ball, which is 9. At which position is the tension in the string the greatest? at the bottom of the circle on the descending side of the circle on the ascending side of the circle at the top of the circle the tension on the string is the same everywhere. I can compare the forces on an object at different positions in vertical circular motion. Apr 11, 2019 · The tension force points towards the center of the circle the entire time, since tension can only act along the cord which is always a radius of the circle. 5. At the lowest point of its motion the tension in the rope supporting the bucket is 23. A 2. 55 m . Physics. 21 m/s. Nov 12, 2023 · When a yo-yo moves in a vertical circle, the force of tension is greater at the top of the circle than at the bottom. 79 m/s. This is because the centripetal force is constantly changing direction, and thus the direction of the tension force also changes. If we wanted to calculate the minimum or critical velocity needed for the block to just be able to pass through the top of the circle without the rope sagging then we would start by letting the tension in the rope approaches zero. Thus tension in the string should be greater than or equal to zero at $\theta = \pi$. 70m/s , then the speed at the bottom will be 7. You swing a 3. Therefore, at the highest point, tension must be greater than 0. 1. This can be calculated as T = m * g + (m * v^2) / r, where T is the tension, m is the mass of the ball, g is the acceleration due to gravity, v is the velocity , and r is the radius of the circle. The rope will not go to slack. A 10. How is this possible? 3) If the velocity at any point ends up zero, does the tension necessarily have to end up equalling zero as well? newtonian-mechanics. m (v 2 /r) = mg. Calculate the tension in the string when the ball is at the bottom. Sep 4, 2023 · At the top of the circle, the tension is equal to the sum of the weight of the ball and the centripetal force required to keep it in circular motion. What is the object's linear velocity at the top of the circle if the tension in the rope at this point is 30 N? 10 m/s; 8 m/s; 9 m/s; The work done by the centripetal force acting on an object moving at a constant linear speed is: Sep 5, 2023 · In a vertical circle, the tension at the topmost point is 0 because at that point, the centrifugal force acting on the object is equal to the weight of the object. At the lowest point of its motion the tension in the rope supporting the bucket is 26. it and T', have magnitudes Tt and T). 10 kg is whirled in a vertical circle of radius 1. The velocity of the bucket at the top of th …. org You can swing a ball on a string in a vertical circle if you swing it fast enough. 25 m . 97 s. ) (gr)1/2C. 21. 75; 1. 5 m long is used to whirl a 1 kg stone in a vertical circle at uniform speed of 5 ms. Neglecting the force of gravity on the body, predict whether or not the string will break. A 900g ball moves in a vertical circle on a 1. 05 m. If the tension is zero at this point, then the weight of the body provides necessary centripetal force to loop in a vertical circle. Its speed at the bottom is 8. Jan 16, 2020 · Solution: Ans: Velocity of stone at the lowermost point = 4. What is the tension in the string when the ball is at the bottom? Figure 6. 400 mFc = 1. When the tension is 0 then the rope has just become slack. Vertical Circular Motion Using a String So at Z, velocity should be such that the weight is equal to the centripetal force, making tension just to be zero. 0 m/s, then the speed at the bottom will be 7. 9 A particle is kept at rest at the top of a sphere of diameter 42 m. (You might try this activity yourself outside with a small plastic bucket half-filled with water. 772 m / s v = 3. For a mass m = kg, the tension at the top of the circle is Ttop = Newtons. 5 kg ball is attached to a 0. Consider the forces acting on a ball when it is swung fast enough in a Mar 20, 2023 · A 0. At the bottom, that means tension is UPWARD while gravitational force is directed DOWNWARD. 8 m long. ) 2 (gr)1/2. motion the tension in the rope supporting the bucket is 25. Express your answer to three significant figures and include the appropriate units. 90 kg is whirled in a vertical circle of radius 1. This is the required minimum velocity at the lowest point of the vertical circle. At the bottom of the circle, the mass is observed to have a speed of 10 m/s. See full list on physics-network. Step 1. The two are in opposite directions, not the same direction. 5 kg. At the top of the circle the speed of the bucket is 3. c. At the lowest point of its. Sep 1, 2015 · $\begingroup$ That the tension in the rope must be 0 for this to happen is simply a consequence of the fact that as long as there is tension, the rope is apparently holding in the body. The value of tension in string is T =mg[x√2−2] when string makes 45° with the vertical, then the value of x is. 90 m/s . The tangential velocity is 200. 150 kg ball on the end of a 1. 62 m, and the tension in the string when the ball is at the top of the circle is 4. Since the mass is moving in a circle then the total force in the radial direction is T - MG*$\cos\theta$ = M*(V^2)/R and so T = MG*$\cos\theta$+M*(V^2)/R but since MG applies acceleration in the tangential direction then V should also be a function of $\theta$ and that is where I kind of got lost. The figure (figure 1) shows two balls of equal mass moving in vertical circles Is the tension in string A greater than less than, or equal to the tension in string B if the balls travel ov<< the top of the circle with equal speed? The tension in string A is greater than the tension in string B The tension in A 6. a. odbiolof mac h ar A 0. 8 N Maximum speeds for curves depend on the weather conditions due to their effect on the coefficient of friction. How fast must the bucket move at the top of the circle so that the rope does not go slack? It is whirled in a vertical circle. What is the magnitude of the tension in the string at that point Motion in a Vertical Circle. 0 N. Determine the tension in the string when the stone is (i) at the top of the circle (ii) at the bottom of the circle. T = m (v 2 /r) - mg. Problem 3: An object of mass 2 kg attached to a string of length 1 m is whirled in a vertical circle at constant angular speed if the maximum tension in the string is 10 kg wt. 50 m/s, then the speed at the bottom will be 7. 2 kg object is whirled in a circle of radius 1. Therefore, when finding the minimum velocity for an object to make it around a loop, we solve for when the tension at the top is zero as it is the minimum possible tension for the object to keep Oct 22, 2016 · The tension in the rod does become zero, at exactly the same point as for the string. The particle is given a horizontal velocity of 10 m/s at lowest point. The minimum centripetal acceleration must therefore = g Formula for centripetal acceleration: a_c = v^2/r where v = velocity (ms^-1) and r = radius (m) At minimum The ball swings at a constant speed in a vertical circle of radius R with the other end of the string held fied. When the ball is at its lowest point, is the tension in the string greater than, less than, or equal to the ball's weight. 0-g ball at the end of a string is swung in a vertical circle with a radius of 25. 0 m/s and its mass is 0. 20 m . Does the tension in the string change as the ball moves around the circle? Yes, the tension in the string changes as the ball At. 0-kg object attached to the end of a 4. Gravity IS the centripetal force at the top of the hill. 3. 5 A ball at the end of a string is revolved in a vertical circle of radius 0. 5 m with constant velocity are in the ratio 5:3 then its velocity is [Pb. 5; 0. Remember in that situation the ball is 45 degrees to the right of the top. The difference is that the rod does not buckle and go limp like the string when the tension decreases even further and becomes -ve. Hence, tension can be zero at the highest. 5 kg tied to a string is projected with a velocity of 10 m s − 1. At the top of the circle, the tension in the string must provide enough centripetal force to keep the object moving in a circle, while also counteracting the force of gravity. Science; Physics; Physics questions and answers; You can swing a ball on a string in a vertical circle if you swing it fast enough. At the lowest point of its motion the tension in the rope supporting the bucket is 31. during one revolution is 2 m g r B) difference of maximum tension and minimum tension in the string is 6 m g For a sum-of-forces to keep you moving in a uniform circle, $\theta = \omega~t+\theta_0$ and then $\ddot \theta = 0$ and the first term goes away; if your circle is vertical rather than horizontal then generally your bucket will be going faster near the bottom than the top and so this first term also matters -- but it's not what you're asking Why is the tension at the top of a vertical circle different from the tension at the bottom of a vertical circle? Your solution’s ready to go! Our expert help has broken down your problem into an easy-to-learn solution you can count on. In a vertical circle of radius (r), at what point in its path a particle may have tension equal to zero:. A child is swinging a 360-g ball at the end of a 73. The tension changes in a vertical circle and is greater at the bottom and less at the top than the weight force. 00 m/s at that position? 46. There are 3 steps to solve this one. 5 m. The velocity of the stone at the bottom of the circle is just sufficient to take it to the top of the circle without slackening of the string. determine the tension in the string at the top of the circle. 33m/s . Mar 18, 2022 · Give a reason for your answer. towards center of the circle (which is down and to the left at 45 degrees). 050 kg yo-yo is swung in a vertical circle on the end of its 0. PET 2003] (a) 198 m/s (b) 7 m/s (c) 490 m/s (d) 4. 7:28. The maximum and minimum tension in the string whirling in a circle of radius 2. 00 kg object swings on a 2. A body weighing 0. Question: a ball of mass m at the end of a string moves in a vertical circle of radius r with constant energy e. 15 kg steel ball is tied to the end of a string and then whirled in a vertical circle at a constant speed v. 30 m long string at the slowest speed that the yo-yo can have. 00 m/s at the top of the circle, the tension in the string has a magnitude of: A 0. If the cord is slack at the top then tension is $0$. The corresponding tension at the bottom of the circle is Tbottom = Newtons. ) (2gr)1/2B. Explain and include FBD. if the difference between maximum and minimum tension in the rope is 20 N, mass of the stone in K g is (g = 10 m / s 2) 0. Now, how can tension be zero upward? Even if it is zero, why doesn't it slack then? Then the book jot down an equation: A bucket of mass 1. 4 m). Jun 30, 2021 · Hence, tension at lowermost point is 117. 0 N Find the speed of the bucket. We use the formula: T + mg = m(v^2)/r Question: 10. 5 cm). Oct 25, 2021 · Draw a diagram of the situation. What is the tension on the rope with it is at the top position? A) 140 N C) 220 N E) 380 N B) 180 N D) 360 N Jan 17, 2020 · In this case, a 2. The tension in the string provides the required centripetal force to keep the object moving in a circular path. At the top of the vertical circle, the tension force is very small; and at the bottom of the vertical circle, the tension force is very large. Explain why there's a minimum speed to keep the ball moving in a circle. Find the speed of the bucket. 137 kg. 920 m . Why do we say that the tension is 0? Tension and the force of gravity act downward so wouldn't they add up causing the string to slacken even if tension were positive? A body weighing 0. Calculate the period of the motion. . Give extra caution to stay clear of all people, windows, trees and overhead power lines. Now, the above equation can be written as, v = r 0 + m g m = r m g m = r g. It isn't a matter of perspective. 61 N. Minimum speed required by the particle at the highest point to complete the vertical circular motion is √ (g r). highest point; lowest point; at any point; at a point horizontal from the centre of radius Feb 24, 2023 · The tension in the rope at the top of the swing can be found using the equation for centripetal force. The stone's speed at this point is given byA. 30 kg is whirled in a vertical circle of radius 1. So I split up gravity into two perpendicular components. a) Tension at the top. 8 N 107 N 58. string. As R increases, just at the moment the normal force becomes zero, the car is still undergoing uniform circular motion at that vertical position. 5 m length of a string, which can withstand a tension of 15 N. The body starts whirling in a vertical circle. 00 m with a linear speed of 20 m/s ? What would be the tension in the rope at the top and the bottom of the swing if it were whirled in a vertical Apr 15, 2015 · The particle will complete the circle if the string does not slack even at the highest point ie. Minimum Velocity required to Loop in the Vertical Circle. Figure 1 of 1 > Р M L Part A Find T. Find the tension in the rope tied to the bucket Your solution’s ready to go! Our expert help has broken down your problem into an easy-to-learn solution you can count on. 20-kg object attached to the end of a string swings in a vertical circle (radius = 80 cm). 6 N, when string is horizontal is 58. (8 marks) a) What is this speed at the top of the circular path? Include a labelled free-body diagram with your answer. (b) How fast must the bucket move at the top of the circle so that the rope does not go slack? Show all work, please! Step 1. 00 m with a linear speed of 20 m/s ? b. 30 kg mass attached to the end of a string swings in a vertical circle (R = 1. 0 kg block rests on a frictionless surface and is attached to a vertical peg by a rope. ) 2grD. The direction of the instantaneous tangential velocity is shown at two points along the path. 20 m × 9. Explanation: The physics behind the 'Around the World' yo-yo trick involves concepts of centripetal force and tension Question: Vertical Circle: A 0. A. The length of the string is 0. 70 kg is whirled in a vertical circle of radius 1. 05 ms^-1 The acceleration required to keep the water following the circumference of the circle a_c (called centripetal acceleration) must be >= g (acceleration due to gravity) to prevent the water from spilling. 8 N, and tension at topmost point is 0 N. Determine the minimum speed the ball must have at the top of its arc so that it continues moving in a circle. 8 m, find the tension in the string when the body is (i) at the top of the circle and (ii) at the bottom of the circle. (a) a drop of rain falling down with a constant speed. ps oc ao pe ue qv gs eb vc kw